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'nother math problem - Dumb_Polack - 07-12-2019
Let's say the earth is smooth all the way around at the equator. Let's also say that if I string a line around the equator it would be snug to the surface of the earth, correct?
Now, If I cut that string and add just 20 feet to it you would grant me that it would now be lose around the equator, correct? (sorta like a belt that's too big for your gut).
Here's the question: is it lose enough for a person to be able to crawl under it? Remember, I'm just adding 20 ft to a circle that's 7K (approx) mile in diameter.
Yes/no? Also prove your answer one way or the other.
RE: 'nother math problem - Dumb_Polack - 07-12-2019
C'mon, no one wants to take a stab at it???
RE: 'nother math problem - Cooler - 07-12-2019
The circumference of the earth is 24,901 miles = 131,477,280 feet.
The diameter of the earth would be then 418,505,015 feet.
Add 20 feet to the circumference = 131,477,300 feet.
The new diameter is 418,505,021 feet.
If you are under 6 feet tall you could walk under it.
RE: 'nother math problem - Large Wooden Badger - 07-12-2019
I don't think you could fit under it. Just because the circumference is 6 feet more, spread out over that distance its probably less than an inch at any particular point.
RE: 'nother math problem - Edwin Hackleman - 07-12-2019
(07-12-2019, 09:55 AM)Cooler Wrote: The circumference of the earth is 24,901 miles = 131,477,280 feet.
The diameter of the earth would be then 418,505,015 feet.
Add 20 feet to the circumference = 131,477,300 feet.
The new diameter is 418,505,021 feet.
If you are under 6 feet tall you could walk under it.
Close but not quite. Simpler method is that if you add 20' to the circumference you gain 20/pi to the diameter. where pi is about 355/113 or 3.1416. That's 6.4', so the radius goes up half that or 3.2'. If your child is 3' tall, he/she could walk underneath the string all the way around the globe.
RE: 'nother math problem - Cooler - 07-12-2019
(07-12-2019, 09:57 AM)Large Wooden Badger Wrote: I don't think you could fit under it. Just because the circumference is 6 feet more, spread out over that distance its probably less than an inch at any particular point.I didn't do the math. I relied on a circumference/diameter calculator online.
The diameter grew by 6 feet, not the circumference.
RE: 'nother math problem - Dumb_Polack - 07-12-2019
Yes you can! Here's the proof. from 4th grade math you'll remember that:
C= 2 (pi)r
Now, the C will increase by 20 ft, correct? That'll cause the r to increase by (x), right? So, let's write that down:
C +20 = 2* pi(r+x)
Factor it out and you get:
C +20 = 2*pi+r +2*pi*x
but from above C = 2*pi*r, correct? So I'll just substitute C on the LH side of the equation for this and you get:
2*pi*r +20 = 2*pi*r + 2*pi*x
now let's drop the 2+pi*r from both sides of the equation and you're left with:
20 = 2*pi*x, right? move the 2 to the other side by dividing and you get:
10 = pi*x Let's call pi = 3.141 so dividing 10 by that and you get approx 3.18 ft, more than enough room for someone to crawl under
As a side note, since the r factors out, it doesn't matte the size of your circle (i.e. you could tie a string around the universe (assuming it is round)) and you'd get the same results.
Pretty slick, eh?
RE: 'nother math problem - Cooler - 07-12-2019
(07-12-2019, 10:14 AM)Edwin Hackleman Wrote: Close but not quite. Simpler method is that if you add 20' to the circumference you gain 20/pi to the diameter. where pi is about 355/113 or 3.1416. That's 6.4', so the radius goes up half that or 3.2'. If your child is 3' tall, he/she could walk underneath the string all the way around the globe.
I figured to pull up the string in one place for my needs only.
The question was could a person crawl under it (which implied one person at one location). I was not worried about children in Australia walking under the string, only if I could walk under the string.
RE: 'nother math problem - AHill - 07-12-2019
(07-12-2019, 09:55 AM)Cooler Wrote: The circumference of the earth is 24,901 miles = 131,477,280 feet.
The diameter of the earth would be then 418,505,015 feet.
Add 20 feet to the circumference = 131,477,300 feet.
The new diameter is 418,505,021 feet.
If you are under 6 feet tall you could walk under it.
The math is correct.
If the rope is equally suspended above the earth, it would be half the 6 feet or 3 feet. So you'd need to do the limbo to walk under it - or be very short in stature.
It would be easier to step over the rope than to walk under it. Just let the extra 20 feet fall to to the surface.
RE: 'nother math problem - FrankAtl - 07-12-2019
(07-12-2019, 09:55 AM)Cooler Wrote: The circumference of the earth is 24,901 miles = 131,477,280 feet.
The diameter of the earth would be then 418,505,015 feet.
Add 20 feet to the circumference = 131,477,300 feet.
The new diameter is 418,505,021 feet.
If you are under 6 feet tall you could walk under it.
Hmmm...don't think I've ever seen a circle with the diameter larger than the circumference.
